How far is Warrensburg, MO from O'Fallon, MO?
Distance by Flight
Shortest distance between Warrensburg and O'Fallon is 163.55 miles (263.2 km).
Flight distance from Warrensburg, MO to O'Fallon, MO is 163.55 miles. Estimated flight time is 00 hours 22 minutes.
It takes 00 hours 20 minutes to travel from Warrensburg to O'Fallon with an airplane (average speed of 550 miles).
Driving distance
The driving distance from Warrensburg, Missouri to O'Fallon, Missouri is: 185.35 miles (298.3 km) by car.
Driving from Warrensburg to O'Fallon will take approximately 02 hours 51 minutes.
#1 Warrensburg
City in Missouri
| Population | 20539 |
|---|---|
| GPS Coordinates | 38°45'46"N 93°44'10"W |
| Latitude | 38.7627900 |
| Longitude | -93.7360500 |
| Altitude | 263 |
| Country | United States |
#2 O'Fallon
The most populous city in St. Charles County, Missouri. It is located in the eastern part of the county. O'Fallon is known for its many parks and green spaces, its many historical sites, and its many attractions, such as the O'Fallon City Hall and the O'Fallon History Museum.
| Population | 89769 |
|---|---|
| GPS Coordinates | 38°48'38"N 90°41'59"W |
| Latitude | 38.8106100 |
| Longitude | -90.6998500 |
| Altitude | 165 |
| Country | United States |
Ending point in O'Fallon: (-90.699849,38.810674)
Estimated Travel Time Between Warrensburg and O'Fallon
The distance between Warrensburg and O'Fallon is 298 km if you choose to drive by road. You can go 03 hours 18 minutes if you drive your car at an average speed of 90 kilometers / hour. For different choices, please review the avg. speed travel time table on the below.
There is no time difference between Warrensburg and O'Fallon. The current time is 08:43:46.
| Average Speed | Travel Time |
|---|---|
| 30 mph (48.3 km/h) | 06 hours 10 minutes |
| 40 mph (64.37 km/h) | 04 hours 38 minutes |
| 50 mph (80.47 km/h) | 03 hours 42 minutes |
| 60 mph (96.56 km/h) | 03 hours 05 minutes |
| 70 mph (112.65 km/h) | 02 hours 38 minutes |
| 75 mph (120.7 km/h) | 02 hours 28 minutes |
| 80 mph (128.75 km/h) | 02 hours 18 minutes |
Gas Consumption
A car with a fuel efficiency of 8.3 l/100 km will need 24.76 liters (6.54 gallon) of gas to cover the route between Warrensburg and O'Fallon.
The estimated cost of gas to go from Warrensburg to O'Fallon is $20.96 (diesel $28.95).
Missouri gas prices.
| Gasoline | Mid Grade | Premium | Diesel | |
|---|---|---|---|---|
| Gallon | $3.21 | $3.54 | $3.86 | $4.43 |
| Total | $20.96 | $23.13 | $25.25 | $28.95 |
Take a look at our Gas Cost Calculator feature. It will figure out how much it will cost to drive this particular distance.
The average gas price (in Missouri ) per gallon of daily gas for calculations is $3.205 (Diesel $4.426) /gallon. Last changed prices on December 22, 2024.
How did we calculate the distance?
The place names are translated into coordinates to approximate the distance between Warrensburg and O'Fallon (latitude and longitude). Cities, states, and countries each have their own regional center. The Haversine formula is used to measure the radius.
Distance to Other Cities
Driving distance from New York, MO to Warrensburg 76.38 miles (123 km)
Driving distance from Castle Point, MO to Warrensburg 212.46 miles (342 km)
Driving distance from East Independence, MO to Warrensburg 52.67 miles (85 km)
