How far is Warrensburg, MO from Jefferson City, MO?
Distance by Flight
Shortest distance between Warrensburg and Jefferson City is 85.27 miles (137.22 km).
Flight distance from Warrensburg, MO to Jefferson City, MO is 85.27 miles. Estimated flight time is 00 hours 10 minutes.
It takes 00 hours 09 minutes to travel from Warrensburg to Jefferson City with an airplane (average speed of 550 miles).
Driving distance
The driving distance from Warrensburg, Missouri to Jefferson City, Missouri is: 90.31 miles (145.34 km) by car.
Driving from Warrensburg to Jefferson City will take approximately 01 hours 37 minutes.
#1 Warrensburg
City in Missouri
| Population | 20539 |
|---|---|
| GPS Coordinates | 38°45'46"N 93°44'10"W |
| Latitude | 38.7627900 |
| Longitude | -93.7360500 |
| Altitude | 263 |
| Country | United States |
#2 Jefferson City
The capital of Missouri. It is located on the east bank of the Missouri River in the central part of the state. Jefferson City is known for its many parks and green spaces, its many historical sites, and its many attractions, such as the Missouri State Capitol and the Jefferson City Museum of History and Art.
| Population | 42708 |
|---|---|
| GPS Coordinates | 38°34'36"N 92°10'25"W |
| Latitude | 38.5767000 |
| Longitude | -92.1735200 |
| Altitude | 192 |
| Country | United States |
Ending point in Jefferson City: East Wall Way (-92.173431,38.576776)
Estimated Travel Time Between Warrensburg and Jefferson City
The distance between Warrensburg and Jefferson City is 145 km if you choose to drive by road. You can go 01 hours 36 minutes if you drive your car at an average speed of 90 kilometers / hour. For different choices, please review the avg. speed travel time table on the below.
There is no time difference between Warrensburg and Jefferson City. The current time is 08:29:19.
| Average Speed | Travel Time |
|---|---|
| 30 mph (48.3 km/h) | 03 hours 00 minutes |
| 40 mph (64.37 km/h) | 02 hours 15 minutes |
| 50 mph (80.47 km/h) | 01 hours 48 minutes |
| 60 mph (96.56 km/h) | 01 hours 30 minutes |
| 70 mph (112.65 km/h) | 01 hours 17 minutes |
| 75 mph (120.7 km/h) | 01 hours 12 minutes |
| 80 mph (128.75 km/h) | 01 hours 07 minutes |
Gas Consumption
A car with a fuel efficiency of 8.3 l/100 km will need 12.06 liters (3.19 gallon) of gas to cover the route between Warrensburg and Jefferson City.
The estimated cost of gas to go from Warrensburg to Jefferson City is $10.21 (diesel $14.1).
Missouri gas prices.
| Gasoline | Mid Grade | Premium | Diesel | |
|---|---|---|---|---|
| Gallon | $3.21 | $3.54 | $3.86 | $4.43 |
| Total | $10.21 | $11.27 | $12.3 | $14.1 |
Take a look at our Gas Cost Calculator feature. It will figure out how much it will cost to drive this particular distance.
The average gas price (in Missouri ) per gallon of daily gas for calculations is $3.205 (Diesel $4.426) /gallon. Last changed prices on December 22, 2024.
How did we calculate the distance?
The place names are translated into coordinates to approximate the distance between Warrensburg and Jefferson City (latitude and longitude). Cities, states, and countries each have their own regional center. The Haversine formula is used to measure the radius.
Distance to Other Cities
Driving distance from New York, MO to Warrensburg 76.38 miles (123 km)
Driving distance from Castle Point, MO to Warrensburg 212.46 miles (342 km)
Driving distance from East Independence, MO to Warrensburg 52.67 miles (85 km)
