How far is Lake Winnebago, MO from Saint Charles, MO?
Distance by Flight
Shortest distance between Lake Winnebago and Saint Charles is 208.77 miles (335.98 km).
Flight distance from Lake Winnebago, MO to Saint Charles, MO is 208.77 miles. Estimated flight time is 00 hours 27 minutes.
It takes 00 hours 25 minutes to travel from Lake Winnebago to Saint Charles with an airplane (average speed of 550 miles).
Driving distance
The driving distance from Lake Winnebago, Missouri to Saint Charles, Missouri is: 229.82 miles (369.86 km) by car.
Driving from Lake Winnebago to Saint Charles will take approximately 03 hours 45 minutes.
#1 Lake Winnebago
City in Missouri
| Population | 1370 |
|---|---|
| GPS Coordinates | 38°49'53"N 94°21'31"W |
| Latitude | 38.8314000 |
| Longitude | -94.3585600 |
| Altitude | 295 |
| Country | United States |
#2 Saint Charles
A city in St. Charles County, Missouri. It is located on the Missouri River in eastern Missouri. Saint Charles is known for its many parks and green spaces, its many historical sites, and its many attractions, such as the Lewis and Clark National Historic Trail and the Saint Charles City Museum.
| Population | 71761 |
|---|---|
| GPS Coordinates | 38°47'2"N 90°28'52"W |
| Latitude | 38.7839400 |
| Longitude | -90.4812300 |
| Altitude | 147 |
| Country | United States |
Ending point in Saint Charles: North Second Street (-90.481269,38.783952)
Estimated Travel Time Between Lake Winnebago and Saint Charles
The distance between Lake Winnebago and Saint Charles is 370 km if you choose to drive by road. You can go 04 hours 06 minutes if you drive your car at an average speed of 90 kilometers / hour. For different choices, please review the avg. speed travel time table on the below.
There is no time difference between Lake Winnebago and Saint Charles. The current time is 10:12:12.
| Average Speed | Travel Time |
|---|---|
| 30 mph (48.3 km/h) | 07 hours 39 minutes |
| 40 mph (64.37 km/h) | 05 hours 44 minutes |
| 50 mph (80.47 km/h) | 04 hours 35 minutes |
| 60 mph (96.56 km/h) | 03 hours 49 minutes |
| 70 mph (112.65 km/h) | 03 hours 16 minutes |
| 75 mph (120.7 km/h) | 03 hours 03 minutes |
| 80 mph (128.75 km/h) | 02 hours 52 minutes |
Gas Consumption
A car with a fuel efficiency of 8.3 l/100 km will need 30.7 liters (8.11 gallon) of gas to cover the route between Lake Winnebago and Saint Charles.
The estimated cost of gas to go from Lake Winnebago to Saint Charles is $25.99 (diesel $35.89).
Missouri gas prices.
| Gasoline | Mid Grade | Premium | Diesel | |
|---|---|---|---|---|
| Gallon | $3.21 | $3.54 | $3.86 | $4.43 |
| Total | $25.99 | $28.68 | $31.3 | $35.89 |
Take a look at our Gas Cost Calculator feature. It will figure out how much it will cost to drive this particular distance.
The average gas price (in Missouri ) per gallon of daily gas for calculations is $3.205 (Diesel $4.426) /gallon. Last changed prices on November 24, 2024.
How did we calculate the distance?
The place names are translated into coordinates to approximate the distance between Lake Winnebago and Saint Charles (latitude and longitude). Cities, states, and countries each have their own regional center. The Haversine formula is used to measure the radius.
Distance to Other Cities
Driving distance from Castle Point, MO to Lake Winnebago 242.61 miles (390 km)
Driving distance from East Independence, MO to Lake Winnebago 23.73 miles (38 km)
